2006-10-04 18:01:10 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
its in joules
2006-10-04 18:01:47 · update #1
if that helps any
2006-10-04 18:03:01 · update #2
90500
You round the third number from the left and make the rest zeros. 90535.744 to three significant figures means that it is around 90500.
2006-10-04 18:04:53 · answer #1 · answered by Alex 3 · 0⤊ 0⤋
In this case take the 3 figures on the seft, since the 1st is non-zero. So,
90,535.744 becomes
90,500.0.
Your rounding error is 0.04%
2006-10-05 01:08:22 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋
it is "90500" . the 2 zeros at the end are place holders. If it were "90500." (with decimal) then it would be 5 significants
2006-10-05 01:07:22 · answer #3 · answered by Mr. Felix 2 · 0⤊ 0⤋
9.05 x 10^4
2006-10-05 01:08:32 · answer #4 · answered by craig p 2 · 0⤊ 0⤋
905x10^2
2006-10-05 02:04:49 · answer #5 · answered by RichUnclePennybags 4 · 0⤊ 0⤋
905x10^2 or 9.05x10^4
Zeros like 90500 infer a precision you don't have.
2006-10-05 02:13:16 · answer #6 · answered by slatibartfast 3 · 0⤊ 0⤋
9.054 x 10^4
i think.
2006-10-05 01:04:14 · answer #7 · answered by nsis88 1 · 1⤊ 1⤋
90500 perhaps?
2006-10-05 01:04:02 · answer #8 · answered by Anon 2 · 1⤊ 0⤋