Here is the problem, " a calorimeter is filled with 150.0 g of water at 24.10 degrees C. A 50.0 g sample of metal at 100.0 degrees C is dropped into this calorimeter and causes the temperature to increase a total of 5.40 degrees C. What is the specific heat of the metal?
I understand how to calculate J/g C, (q=mc* change in temp [C]), how do I find specific heat (c) when I don't know the heat absorbed by the calorimeter?
2006-10-05 03:35:45 · 3 answers · asked by historybuff2009 2 in Science & Mathematics ➔ Chemistry
You assume all the energy goes into heating the water.
State the assumption in your answer.
2006-10-05 03:56:20 · answer #1 · answered by Dr. J. 6 · 0⤊ 0⤋
I think in these problems, you assume the calorimeter absorbs no heat.
2006-10-05 10:44:35 · answer #2 · answered by bequalming 5 · 1⤊ 0⤋
qlost = q gained
2006-10-05 11:23:38 · answer #3 · answered by shiara_blade 6 · 0⤊ 0⤋