The limit as x→-∞ of (x + the square root of (x^2 + 2x)). I have to solve it algebraically. I keep getting DNE but when I graph it, the answer looks like it should be -1. Can you please show detailed work on how to do this problem or a similar one. Here's what I've tried but obviously something is wrong: *sq stands for square root of---
x + sq(x^2 + 2x) * (x – sq(x^2 +2x))
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1* ((x – sq(x^2 +2x))
x^2 – (x^2+2x)
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x – sq(x^2 +2x)
-2x / x
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(x-sq(x^2 + 2x))/x
-2
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1-sq(1-(2x^-.5))
I took the limits of each part to get:
-2
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1-sq(1-0)
-2
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0
DNE
It might be easiest to write this out on paper first because I couldn't type alll the mathamatical symbles -Thanks
2006-10-07
16:19:24
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2 answers
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asked by
jazzyrhythms
3
in
Mathematics