So the question goes like this:
A TV camera at ground level is filming the liftoff of a space shuttle that is rising vertically according to the position eqn: s(t)=50t^2, where s is measured in feet and t is measured in seconds. The camera is 2000 feet from the launch pad.
Find the velocity of the space shuttle when it is 5000ft high.
[[I did this already, and I got 1000 ft/s. I know that it is right.]]
Find the rate of change in the angle of elevation of the camera when the space shuttle is 5000 ft. high.
[[I can't figure this one out for the life of me. I think it has something to do with inverse tangent, and with the previous anwser (1000 ft/sec).]]
If you can solve this, you're my hero and a freaking genius!!
2007-12-18
07:34:08
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1 answers
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asked by
hp_ddocd
1