Thanks for helping with my math questions. I'm helping my bf with his homework, but I took algebra 2 two years ago and my brain is foggy...
This problem says:
Find two consecutive odd intergers such that the square of the first increased by the second is 32.
Logically I know that 5^2 is 25, and 25 plus 7 is 32. 5 and 7 are consecutive and odd....
here's where my problem comes in.
My boyfriend has to have an equation and putting this into an equation I would get:
n^2 + (n + 2) = 32
n^2 + n - 30 = 0
(n+6) (n-5)= 0
This means that according to equation form, the numbers are 5 and 6. However 6 is not odd and 5^2 + 6 is 31...
Am I missing something? Did I write the equation wrong?
2006-10-15
16:10:39
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5 answers
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asked by
Anonymous