Hi. I have a question about this heredity probabilty. We are doing this in my biology class and I am confused. Here is some questions:
Indicate the probability of obtaining the genotype in an offspring.
AAbb x AaBb and the offpsring is AAbb (i put 1/4)
AABbcc x aabbCC and offspring is AaBbCc (1/4)
AaBbCc x AaBbcc and off is aabbcc (1/32)
Then it gives me three traits.
Flower posiiton Axial(A) Termial(a)
Stem length Tall(T) Short(t)
Seed shape Round(R) Wrinkled (r)
if plant is heterozygous for all traits, probabilty for
a. homzygous for al dominant traits (i put 3/4)
b. homozyhous for three rec traits (1/4)
c. heterozegous for three thraits (6/36=1/6)
d. Homo for axial and tall, hetero for round (2/36 x 1/3 = 1/54)
Finally it says a disease is determined by a rec allele. if husband and woman are both carrier, prob of.
a. all three children normal (3/4)^3
b. one or more of the three children have disease (1/4+1/4+1/4=3/4)
d. at least one child will be normal (No idea)
any help?tnks!
2006-09-27
11:55:23
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1 answers
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asked by
anoc
1