Equation of the line:
(x-1)/3 = (y+3)/1 = (z)/2
Given point (2,3,1)
Find the equation of the plane that has this line and point.
____________________
OK so I got to this point:
In vector form, r(t) = (1,-3,0) + t(5,1,2)
Let t = 0 then (1,-3,0) is in the plane
Let t = 1 then (6,-2,2) is in the plane
So I now have 3 points on the plane. How do I use this to find the equation of the plane?
If I assign "P,Q,R" to these and use:
n = (q-p) x (r-p) = (x,y,z) etc.
Does it matter what point is assigned to P,Q or R? This is what I can't get my head around.
2007-12-13
11:24:14
·
1 answers
·
asked by
Anonymous