Part I)
How do you show that H is not normal in A_4?
Part II)
Referring to the Multiplication table for A_4 as a set of even permutations (http://www.math.niu.edu/~beachy/aaol/grouptables2.html)
how do you show that, althought, X_6H = X_7H and X_9H = X_11H, it is not true that X_6X_9H = X_7X_11H. Why does this prove that the left cosets of H do not form a group under coset multiplication??
(For easier typing, for this problem I am letting alpha = X and the even permutations in the chart are labeled as follows:
(1) = X_1
(12)(34)= X_2
(13)(24)= X_3
(14)(23)= X_4
(123)= X_5
(243)= X_6
(142)= X_7
(134)= X_8
(132)= X_9
(143)= X_10
(234)= X_11
(124)= X_12
2007-11-18
13:23:32
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1 answers
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asked by
Anonymous