I have a math problem 5x squared-15x-20 can anyone please help me solve it?

Answer 1

The word "solve" suggests an equation which , in turn, requires = sign.
Will simplify expression rather:-
5(x² - 3x - 4)
5(x - 4)(x + 1)

Should this = 0 , x = 4 , x = - 1

Answer 2

I think you mean you want to factorise it.
5x²-15x-20 = 5(x²-3x-4) as all the numbers divide evenly into 5.
Now we need two numbers which multiple to give -4 and add to give -3.
They are be -4 and 1.
So 5x²-15x-20 = 5(x-4)(x+1)

Answer 3

factor out a 5
5(x^2 -3x-4)
5(x -4 )(x+1)
this is the answer of you require simplification

as -4 * +1 = -4
and they add up to -3

now you said solve it= that means find x

5(x -4 )(x+1) = 0
now use the zero product on each parenthesis
(x -4 ) = 0 or (x+1) = 0
x=+4 or x=-1

Answer 4

(5x + 5 ) ( x - 4)

to solve for x ;

(5x + 5 ) ( x - 4 ) = 0

5x = - 5 x-4 = 0
x= -1 x = 4

Answer 5

5x^2 - 15x - 20 = 0

5(x^2 - 3x - 4) = 0

(x^2 - 3x - 4) = 0

(x+1)(x-4) = 0

x = -1
x = 4

Answer 6

if u'r lookin fer x and if the eqn = 0

(x-4)(x+1)=0
x=-1,4