If you take any irrational and truncate it
after finitely many decimal places, it becomes
rational, because it is now a terminating decimal.
Example: √2 = 1.4142135...
If I write only the first 3 decimal places, we
have 1.414, which is rational and a rational
approximation to √2.
2007-11-18 13:45:22
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answer #1
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answered by steiner1745 7
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More detail needed in this question.
There are irrational numbers which are not the roots of rational functions and hence you can not just square it or similar to get to a rational number.
A very simple answer would be the ceiling function which rounds any number up to a whole number.
2007-11-18 13:28:44
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answer #2
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answered by Ian 6
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Dividing is faster.
Or subtracting is much faster.
Also, can try:
multiply by 0
raise to the power of 0
floor it
ceiling of it
rounding it up/down
Finally, I think truncating it is a quick/easy/useful way as the result is approximately the original number.
2007-11-18 13:26:58
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answer #3
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answered by back2nature 4
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Sqrt(3) is irrational
But Sqrt(3) * Sqrt(3) = 3 which is rational
2007-11-18 13:25:54
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answer #4
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answered by Jeƒƒ Lebowski 6
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that will only happen if you multiply it by itself if it is an even root.
root2 * root 2 = 2
root(a) *root(a) = a
if it is a cube root it is a little more difficult,
i would look at www.purplemath.com as a reference
2007-11-18 13:25:30
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answer #5
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answered by a c 7
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