English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

Mathematics - 18 August 2006

[Selected]: All categories Science & Mathematics Mathematics

is
a^(2)-b^(2)
=(a-b)^(2)+2b(a-b)
true?

2006-08-18 23:59:57 · 9 answers · asked by rajesh bhowmick 2

I m under graduation student and my age is 22

2006-08-18 23:49:58 · 24 answers · asked by Valcano 1

2006-08-18 23:46:38 · 10 answers · asked by Anonymous

I think in fermats last theorem we have to do the work for powers which are primes or the factors of the power is the prime with the same value such as 4(2*2),49(7*7), Because for non prime powers such as 21 we have to prove only the cubic case or the case for fifth power & if we prove the case of fifth power alone then the case of power 25(5*5) or 125(25*5) is getting proved by itself.Similarly if we prove the 4th power case then the other cases where the factors of the power is only two is getting proved.
In the equation a^(n)-b^(n)=x^(n) or x^(n)+b^(n)=a^(n){fermats last theorem}One more thing is there in it that if "a" has to be even then either "x" & "b" has to be either both odd or both even and lastly we will see that "a" will always be odd to make "x" and "b" natural.
it is obvious as
a^(n)-b^(n)=c^(2)-d^(2) like
7^(3)-4^(3)=140^(2)-139^(2) &
x^(n)=z^(2)-y^(2) like
3^(3)=14^(2)-13^(2).
it is all for natural values of a,b,c,d,x,z,y & of course n.
Identify the primes.

2006-08-18 23:40:43 · 2 answers · asked by rajesh bhowmick 2

and then opened every second locker, and then went back and closed every third locker, and went back and opened every fourth locker, and so on...., through alll lockers, any number of lockers...

what lockers would end up open??

2006-08-18 23:02:54 · 11 answers · asked by iandanielx 3

2

1) show that the remainder when 30^99+61^100 is divided by 31 is 0.
2)find the remainder when the sum 1^2 +2^2...+100^2 is divieded by 4.

3) Show that 8|5^2n +7

4) Among the rules of divisibility. Perhaps the most famous one is the "casting-out 9s"rule. A natrual number n is vidisible by 9 if and only if sum of its digits is divisible by 9. Prove it.

2006-08-18 22:12:27 · 9 answers · asked by edwinvandesar 1

it was asked to me by my friend and so i need answers

2006-08-18 21:26:31 · 19 answers · asked by Anonymous

I need all the solution :)

2006-08-18 21:01:08 · 8 answers · asked by Anonymous

2006-08-18 20:42:15 · 18 answers · asked by Anonymous

2006-08-18 20:40:45 · 7 answers · asked by Anonymous

what are the steps to solve this problem?

2006-08-18 20:24:00 · 7 answers · asked by stardust6547 2

2006-08-18 20:21:33 · 10 answers · asked by Anonymous

He is an indian mathematician-aryabhatta.

2006-08-18 20:13:49 · 3 answers · asked by Sakthivel S 1

Here's my problem. I have learned that to convert a repeating decimal into a fraction requires these steps:

Example: to convert the repeating decimal .333333333...

First I let x=.333333333 (that's as many as my calculator can show)

Next I let n=the number of repeating numbers. In this case it's 1.

Then I multiply both sides of the equations x=.333333333 by 10^n or 10^1 (which equals 100)

So the second equation is now 100x=33.333333333

I then subtract the first equation from the second to get:
99x=33

I then divide the 99 to get 33/99 which equals 1/3.

But now if I use the same process to try to find say .416666666 (which is 5/12)
x=.41666666
n=1
multiply 10^1 to both sides to get
100x=41.66666666 subtract the first equation to get
99x=41.249999999
Neither of these numbers is divisible by 5 or 12! Why doesn't this formula work? What am I doing wrong. Please show examples where n=1 as well as n=more than 1.

Thank you.

2006-08-18 19:52:31 · 5 answers · asked by fastreader_12790 1

2006-08-18 19:47:37 · 10 answers · asked by Anonymous

I need to solve (r4 - r3) / (r3 -r2)

I do know all r1,r2,r3,r4 as a ratio of r1
i.e.
r2/r1=a
r3/r1=b
r4/r1=c

where a, b,c are known constants.
So how do I find the ratio (r4-r3) / (r3-r2)
Thanks

2006-08-18 19:37:37 · 14 answers · asked by Anonymous

2006-08-18 19:34:54 · 7 answers · asked by Shravan Vij 1

2006-08-18 19:23:55 · 15 answers · asked by Anonymous

2006-08-18 18:54:10 · 10 answers · asked by Scott R 6

2006-08-18 18:13:40 · 9 answers · asked by SUSAN M 1

has the "2" somewhere between the "1" and the "3"?

2006-08-18 18:11:37 · 4 answers · asked by Scott R 6

Hi,

We all know the first derivative of e^(x^2) is 2xe^(x^2). But how are we to find it using the first derivative. I hope anyone can help me. Thanks a lot!

2006-08-18 18:10:00 · 7 answers · asked by sky_blue 1

2006-08-18 18:06:57 · 12 answers · asked by Clarence A 2

[1] (28 + 38 + 48 + 58 + 68 + 78 + 88 + 98 + 108) to the power 457754..............................................

[2] (x-a)(x-b).........................................(x-y)(x-z)


@@@@@@@@@@@@@@@@@@@@@@@@@@@@

SOLVE THESE PROBLEMS ................THE SOLVER WILL BE GENIUS @@@ IT DOESN'T MATTER TO ME THAT A PERSON GETS TWO POINTS FOR GIVING BOGUS ANSWER BUT IT MATTERS TO ME THAT A PERSON GIVES EFFORT TO IT AND CRACKS THE TRICK OF THESE QUESTIONS ##############

BYE BYE BYE .....................................................*******************

2006-08-18 17:58:47 · 8 answers · asked by fathom_2005 j 1

2006-08-18 17:02:16 · 7 answers · asked by Arun D 2

FInd an equation for the qudratic function described:

Question 1: The minimum value of f is f(f) = -5 and, f(-1) = 2

Question 2: Its graph is a parabola that is tangent to teh x-axis at (4,0) abd has y-intercept 6.

WOULD BE GOOD IF SOMEONE SHOWED ME HOW TO DO THESE 2 PROBLEMS THANKS.

2006-08-18 17:00:08 · 6 answers · asked by asdf123 1

fedest.com, questions and answers