If x² + x – 5 = 0, then x = ?????????

Answer 1

X^2 + X - 5=0

take ^2 as square and ^1/2 as Square root

here a=1, b=1, c= -5

Now
X = {-b +-(b^2 - 4ac)^1/2}/ 2a
= {-1 +-(1 - 4*1*-5)^1/2}/ 2*1
= {-1 +-(1 + 20)^1/2}/ 2
= {-1 +-(21)^1/2}/ 2
now taking the square root of 21 we get

X= {-1 +- 4.58}/2
now X = {-1 + 4.58}/2........or........X= {-1 - 4.58}/2
......X= 3.58/2...............or..............X= - 5.58/2
......X= 1.79................or................X= -2.79

Answer 2

I think it's impossible.

okay, so if make x=2, than 2 to the power of 2 would be four. But then since x=2, the other x is 2. So, pretty much it would be 4+2-5=0 which is wrong.

if u try x=1, 1 to the power to two is 1, so 1 + 1 - 5 = 0 is wrong.

Anything over 2 is wrong. Pretty much this is impossible.

Well, I'm like, teen so i dunno if this is right.

Answer 3

X2 + x – 5 = 0;
Is a quadratic eqn of the form ax2 + bx + c = 0 whose solution is
X = (-b +_ sqrt(b2-4ac))/2a

Substitute a =1; b = 1 c = -5

B2 – 4ac = 21 ; sqrt(21) = 4.58

So -1 + 4.58 = 3.58; 3.58/2 = 1.79

-1 -4.58 = - 5.58; -5.58/2 = -2.79

So x has 2 values, -2.79 and 1.79

Hope that helps.

Answer 4

Hey, how were you able to write x^2 in the proper form.


Anyway you can use the quadratic formula
x=(-b+sqrt(b^2-(4*a*c)))/(2*a) &
x=(-b-sqrt(b^2-(4*a*c)))/(2*a)
In this case a=1,b=1,c=-5


Here is a different solution which I thought it could help you

x^2+x-5=0
x^2+x=5
x=5-x^2

Answer 5

first i wil mention "x to the power of 2 " as "x2" ok
x2 + x - 5 = 0 then x =
x2 + x = 5
x2 = 5-x
x = (root of) 5-x
there it is the answer

Answer 6

The answer clearly isn't an integer, but it's pretty easy to solve using the quadratic formula:

[-b +/- (b^2 - 4ac)^(1/2) ] / 2a.

In this case,

a=1

b= 1

c= -5

You do the math.

Answer 7

D = 1 +4*5 = 21

x1 = (-1 + sqrt(21))/2

x2 = (-1- sqrt(21))/2

Answer 8

x2+x-5=0
x2 means 2x
2x+x-5=0
3x=5
x=5/2
x=2 1/2 means two and half.
Hope this is correct..

Answer 9

continuing from your qn,
x = ( -(1) +/- ( √( (1)[square] - 4(1)(-5) ) ) / 2(1)
= ( (-1) +/- ( √(1 +20) ) / 2
= (-1 + √(21) ) / 2 or = (-1 - √(21) ) / 2
= 1.79 (3 sf) or = -2.79 (3 sf)

Answer 10

quadratic formula
x= (-b+-square root of(b^2-4ac))/2a
a=1
b=1
c=-5

but there is no solution to your question which is x^2+x-5=0
u may study about the complex numbers wherein there is imaginary number.