How to solve this equation?

Question

I need to solve (r4 - r3) / (r3 -r2)

I do know all r1,r2,r3,r4 as a ratio of r1
i.e.
r2/r1=a
r3/r1=b
r4/r1=c

where a, b,c are known constants.
So how do I find the ratio (r4-r3) / (r3-r2)
Thanks

Answer 1

r2 = a*r1
r3 = b*r1
r4 = c*r1

Therefore:

(r4-r3)/(r3-r2) = (c*r1 - b*r1) / (b*r1 - a*r1)
= [ r1 * (c-b) ] / [ r1 (b-a) ]
= (c-b) / (b-a)

Then just plug in and solve.

Answer 2

r2=a x r1
r3=b x r1
r4=c x r1

(r4-r3)/(r3-r2) = (c x r1 - b x r1)/(b x r1 - a x r1) = ((c-b) x r1)/ ((b-a) x r1) = (c-b) / (b-a)

Answer 3

simply...replace r4,r3,r2 in terms of r1 as::(cr1-br1)/(br1-ar1)....taking r1 common and outside,,r1 will get cancelled...so the answer is...(c-b)/(b-a)...

Answer 4

Wishing All the Best for who attempts to Answer this Question !!

Answer 5

according to the question we can see that
r2=ri*a,
r3=r1*b,
r4=r1*c
so the whole equation should be (r1*c-r1*b)/(r1*b-r1*a)
=(r1(c-b))/(r1(b-a))
=(c-b)/(b-a)

Answer 6

go get help from a genius tutor..i dunt get what ur saying...if u could scan the problem, maybe i could solve it 4 u.

Answer 7

ans=(c-b)/(b-a)
wats so wierd in it?r1 gets cancelled

Answer 8

math gives me a headache. is the answer is the same as:

-p1, -p2, -p3, -p4 as a ratio of -p1
i.e.
-p2/p1=-a
-p3/p1=-b
-p4/p1=-c

where -a, -b, -c are unknown unconstants.
how do you find the ratio -(p4-p3)/(p3-p2)
thanks

hmmmmmmmmm see how math can give you a headache?

Answer 9

(r^4 - r^3)/(r^3 - r^2)
(r^3(r - 1))/(r^2(r - 1))
(r^3)/(r^2)
r^(3 - 2)
r

ANS : 4

Answer 10

I don't know how to solve?