The distance between the points (7, -2) and (-3, 1) is ????

Answer 1

d = sqrt[ (7 - (-3))^2 + (-2 - 1)^2 ]
= sqrt[10^2 + (-3)^2]
= sqrt[109]

Answer 2

We have two points at varying positions.
One is (7 , -2) and the other is (-3 , 1).
To find the distance of two points, we first take the difference between the two points i.e.

(7 , -2) – (-3 , 1) = (10 , -3)

Next, we use the formula for finding the distance betw. 2 points. Substituting into the equation with the ans attained above, which is,

√( (10)[square] + (-3)[square] ) = √(100 +9) units

= √(109) units
= 10.4 units (3.sf)

note: if the qn stated the units for the dist between the two points ie. cm, m, etc, then, you ought to replace the units with the correct units ie. 10.4 cm or 10.4 m.
also, if stated, correct ur ans to the correct significant figure or decimal place the question ask for. otherwise, it SHOULD be fine to just leave your ans to 3 s.f.

Answer 3

The distance will be......
[(7+3)^2+(-2-1)^2]^.5
={109}^.5

Answer 4

the distance on x coordinate is 7 - (-3) = 10
the distance on y coordinate is -2 - 1 = 3

10^2 + 3^2 = sqr root of 109

Answer 5

The distance formula actually goes back to 7th grade these days; the answer is sqrt 109

Answer 6

what are u trying to do here.
i mean this is a basic thin in cartesian geometry...

sqrt is suqare root
sqr is square

sqrt(sqr(7-(-3)) + sqr(-2-1))
= sqrt(sqr(10) + sqr(3))
= sqrt(100+9)
= sqrt(109)
=~ 10.44 units of whatever 7,-2,-3 and 1 represent

Answer 7

Use the area formula = sq. root { (x2 - x1)^2 + (y2 - Y1)^2} So, the area between (-a million, 7) and (3,2) = sq. root { (3 +a million)^2 + (2 - 7)^2} = sq. root { (4)^2 + (-5)^2} = sq. root (16 + 25) = sq. root (40-one)

Answer 8

(10^2+(-3)^2)^1/2=(109)^1/2

Answer 9

the equation is simple...learned in grade 11...

the answer is the square root of 109...or 10.44

Answer 10

sqrt(109)