(27a^-3b^6c^3)^1/3?

Question

what are the steps to solve this problem?

Answer 1

(27a^-3b^6c^3)^(1/3)

27^(1/3) * a^(-3 * (1/3)) * b^(6 * (1/3)) * c^(3 * (1/3))

3 * a^(-1) * b^2 * c

ANS : (3b^2c)/a

Answer 2

It's in a complicated form.
The best way to crack this is to substitute the values in one at a time.
Put the value C in, cube it and multiply by 6. Call this value X.
Put the value B in. B is to the power of X, evaluate this and then multiply by -3. Call this value Y.
Now work out the value of 'a' in the power of Y and multiply it by 27. Call this value Z.
Now, get the cube root of Z.
That's your answer.
Good luck.

Answer 3

use P.E.M.D.A.S.
1-parenthesis
2-exponents
3)multiply
4)divide
5)add
6)substract

so solve in the parenthesis first... then you just take what you have solved in the parenthesis and raise that to the 1/3. now you can figure the answer by yourself... all that you asked for was the steps... sorry its way too late at night for me to help you any farther...

Answer 4

Go to bed....

it is not solvable, unless you just want to reduce it

Answer 5

i dont know man that looks complicated.

Answer 6

(a^m)^n=a^mn
(3^3)^1/3*(a^-3)1/3(b^6)1/3*(c^3)^1/3
=3a^-1b^2c

Answer 7

i think your question is wrong