4. At 25°C , the value of Kc for the following reaction is 21.
I2 (g) + Br2 (g) ® 2IBr(g)
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3.26 mol of I2(g) and 1.24 mol of Br2(g) are placed in a 5 L container at 25°C. What are the concentrations of the gases at equilibrium?
5. At a particular temperature, Kc for the following reaction is 3.4 x 10 -5
2CO2(g) ® 2CO (g) + O2
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0.97 mol of CO2 is put in a 3.0 L container. Calculate the equilibrium amount of each gas.
6. At a certain temperature, the value of Kc for the following reaction is 2.1 x 10 -9
2NCl3(g) ® N2 + 3Cl2(g)
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A certain amount of nitrogen trichloride, NCl3(g), is put in a 5.0 L reaction vessel at this temperature. At equilibrium, 3.1 x 10 -3 mol of N2(g) is present. What amount of NCl3(g) was put in the reaction vessel?
These are even more confusing! Oh my god so many steps. They involve Measuring Equilibrium Concentrations. The first one uses a quadratic formula, I think they all do. I tried doing #4 three different ways. First, I think the numbers are too small 0.653 mol/L for example when you try to make the Kc formula into a quadratic one eg. I think you are suppossed to have 2.0 or a larger number before the zero. 0 doesn't work becuase everything you multiply by, is itself?- maybe I should have kept going with that, but I dunno, I don't think so because then after the square root part/step(s) the positive number for x and - number is too large to figure out which one to use compared to my ICE (initial change equilibrium) chart. So then that's as far as I got. The second time I tried flipping n/v around and dividing v/n in the first step to see if that would affect the way the answer(s) turned out. I even tried putting 0.652 mol/L for example in sci. notation to see if that would make a difference, but the numbers don't work out. It's all very new to me- just frustrated, I should be able to get it!
2006-12-05
17:19:42
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1 answers
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asked by
kickaburra
1