The steel I-beam is basically a crane with a triangle it is liftling. the triangle is isosceles with two 70 degree angles and one 40 degree angle. it has a weight of 9.30 kN and is being lifted at a constant velocity. What is the tension in each cable attached to its ends?
i know that the velocity is constant so a=0, and the sum of the forces =0. and i know mg = 9300 N, not 9300*9.8 m/s^2. You do not multiply by 9.8, since you are given the weight, not the mass.
so....
t1~tention 1
t2~tention 2
in the y dirrection: t1 sin theda1 + t2 sin theda2=0
in the x dirrection, t1 cos theda1 + t2 cos theda2=0
i understand that if you make a triangle, t1 is the hypotenuse, t1y=1/2 fg, and t1x would be one the bottom.
so t1y=1/2mg/sin70
that is as far as i could get with this problem. see, i really did try to do it. i just can't finish it. please, PLEASE help me. i really am trying!
2007-10-08
16:27:34
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1 answers
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asked by
Elizabeth
3