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--rest.
The lumberjack runs to the other end of the log, attaining a velocity of +2.8 m/s relative to the shore, and then hops onto an identical floating log that is initially at rest. Neglect any friction and resistance between the logs and the water.

(b) Determine the velocity of the second log if the lumberjack comes to rest on it.

2007-10-09 04:58:21 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

Since he has speed of 2.8 m/s w/r/t shore it is also w/r/t log 2

using conservation of momentum
98*2.8=338*v
v=98*2.8/338

j

2007-10-09 05:39:54 · answer #1 · answered by odu83 7 · 1 0

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