Suppose you have the following probability mass function for the three random variables A, B, anc C:
P_(A,B,C) of (0,0,1) = 5/36
P_(A,B,C) of (0,0,2) = 1/36
P_(A,B,C) of (0,1,0) = 3/36
P_(A,B,C) of (0,1,4) = 3/36
P_(A,B,C) of (0,2,2) = 1/36
P_(A,B,C) of (0,2,3) = 5/36
P_(A,B,C) of (1,0,3) = 2/36
P_(A,B,C) of (1,0,4) = 4/36
P_(A,B,C) of (1,1,2) = 6/36
P_(A,B,C) of (1,2,0) = 4/36
P_(A,B,C) of (1,2,1) = 2/36
How would one find the expected value of B?
2007-10-24
06:47:05
·
2 answers
·
asked by
cornzxo
1