5 times the first of 3 consecutive even integers is 14 more than 3 times the second. What is the third consecutive integer?
10
12
14
16
18
2007-10-24 07:33:56 · 4 answers · asked by kyle p 1 in Science & Mathematics ➔ Mathematics
14
The three consecutive even integers are x, x+2, and x+4
The equation is: 5x=3(x+2)+14
which yields x =10, so the first integers is 10, the second is 12 and the third is 14.
2007-10-24 07:38:38 · answer #1 · answered by Barb 4 · 0⤊ 0⤋
Let the integers be n, n+2, n + 4
5 (n) = 14 + 3(n+2)
5n = 14 + 3n + 6
Subract 3n from each side, and combile like terms.
2n = 20
Divide both sides by 2.
n = 10
CHECK THE ANSWER. IS 5 * 10 EQUAL TO 14 + 3*12?
The third integer is n+4 = 10 + 4 = 14
2007-10-24 07:42:34 · answer #2 · answered by Hiker 4 · 0⤊ 0⤋
let n be the first integer
then n+2 is the next even integer
eq. 5n - 3(n+2) = 14
5n - 3n - 6 = 14
2n = 20
n = 10
so the third integer is 14
2007-10-24 07:40:06 · answer #3 · answered by norman 7 · 0⤊ 0⤋
5(x) = 14+ 3(x+2)
5x = 14 + 3x + 6
2x = 20
x = 10
the numbers are 10, 12 and 14
2007-10-24 07:40:25 · answer #4 · answered by mohanrao d 7 · 0⤊ 0⤋