5.Using the equation you have just derived in four above, calculate the pH of a solution composed of 155 mL of 0.1 M acetic acid and 45 g of sodium acetate. The pKa of acetic acid is 4.76.
First find the moles of sodium acetate:
45g x 1mol/60g = .75mol
Then divide that by the total amount of solution to find the concentration:
.75mol/.155L = 4.84 M
Then plug the concentrations and the pKa into the equation:
pH = 4.76 + log ([4.84]/[0.1])
pH= 6.44
6.What would the pH of this above solution, from five, be after 0.01 mole of HCl was added?
I have no idea how to do this, I don't even know if I got 5 right. I tried.
2007-03-04
10:11:22
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1 answers
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Anonymous