Calculating the Determination of Water in a Hydrate????HELP!!!?
Here are the weights:
Weight of crucible and cover = 12.85grams
Weight of crucible, cover and sample = 16.21grams
Weight of crucible, cover and sample after first heating = 14.82grams
Weight of crucible, cover and sample after second heating = 14.74grams
Weight of crucible, cover and sample after third heating = 14.72 grams
My chemistry teacher wants me to find the calculations of these samples above. I have no F'in idea if I am right or wrong when I am working out this problem.
I think the formula is Percentage of water=(mass lost divided by mass of sample) and then you multiply it by 100.
Here are the directions for the calculations:
Calculate weight of original sample
Numerical setup:
Calculate weight lost from sample by heating
Numerical setup:
Calculate percentage of water in sample
Numerical setup:
For this one, it also asks:
sample No._____
Percentage of water_____
2007-09-24
18:57:25
·
1 answers
·
asked by
danie
2