2C2H2(g) + 5O29g0 → 4CO2(g) + ____
*all but the first "2" is suppose to be lowered.
example: H2O - the "2" is usually lower than the H and the O....make since?
a) 4OH(aq) **4 is NOT lowered
b) CH4(aq) **4 IS lowered
c) H2O2(g) ** both numbers lowered
d) 2H2O(g) **first "2" normal, second "2" lowered
2007-09-24 19:33:22 · 4 answers · asked by XOXO 1 in Science & Mathematics ➔ Chemistry
The number of atoms each element must remain the same after the reaction as it was before. So to figure out what must be the other product you just have to look at how many of each element are accounted for, and how many are "missing."
C: 4 + 0 - 4 = 0
H: 4 + 0 - 0 = 4
O: 0 + 10 - 8 = 2
So which of your choices will give you four hydrogen atoms and two oxygen atoms?
d) 2 H2O
2007-09-24 19:44:15 · answer #1 · answered by endo_jo 4 · 0⤊ 0⤋
d) 2H20
Explanation:
Calculate the number of each atoms on both sides.
There are 4 Carbon, 10 Oxygen and 4 Hydrogen on left-hand side.
There are 4 Carbon, 8 Oxygen and no Hydrogen on right-hand side.
Thus, there are 4H and 2O short. Answer is D.
2007-09-24 19:42:59 · answer #2 · answered by chingmenghang 3 · 0⤊ 0⤋
i think of it may be the 2H2O(g) on the grounds that looks like a combustion reaction which continuously yields CO2 and H2O. And by using how (aq) skill aqueous. that doesn't propose that is water, meaning that is going to dissociate in water and ruin aside.
2016-12-17 09:42:34 · answer #3 · answered by scacchetti 4 · 0⤊ 0⤋
Answer d.
All hydrocarbons burn to form carbon dioxide and water in this way, given enough oxygen.
2007-09-24 19:39:42 · answer #4 · answered by Gervald F 7 · 0⤊ 0⤋