..covalent bond between B-atom and F¯ ion,B atom in BF4¯becomes sp3 hybridized.But this change in state of hybridization of central atom does not take place in case of formation of NH4+ and H3O+ from NH3 and H2O resp. In NH3 and H2O,N-atom and O-atom are sp3 hybridized and the single lone pair in case of the former and the two lone pairs in case of the latter are placed in the sp3 hybrid orbitals which are not involved in the bond formation.On the overlap of such orbital,containing lone pair electrons,in NH3 and one of the two such in H2O,by the empty 1s orbital of H+,NH4+ and H3O+ are formed resp. But in both NH4+ and H3O+,the state of hybridization of N and O remains sp3.So how can I show the formation of BF4¯(ie how to show a vacant 2p orbital of B,perpendicular to the plane of three sp2 hybrid orbitals in BF3,turning to a sp3 hybrid one in BF4¯.). So please explain the change of hybridized state in formation of BF4¯ from BF3..Also suggest a site showing the orbital overlap diagram.
2007-05-19
16:02:33
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2 answers
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Anonymous