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The heat lost by the metal block (originally at 100 degrees C) equals the heat gained by the cold water. If the mass of the metal block is 8.10 grams, the temperature of the cold water extrapolated forward to the time of mixing is 16.3 degrees C, and the temperature of the metal block and water mixture extrapolated back to the time of mixing is 37.0 degrees C, what is the specific heat of the metal? Enter your answer with three significant figures in units of J/K.g.

2007-05-19 06:43:32 · 1 answers · asked by Division12 2 in Science & Mathematics Chemistry

1 answers

Use the formula q = m Cp delta T

Set the same equation for the metal and the water equal to each other. Plug in your numbers and you can solve for the Cp of the metal.

The Cp of water is 4.184 J/g oC

2007-05-19 07:07:33 · answer #1 · answered by reb1240 7 · 0 0

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