Mathematics - 28 October 2007

how to solve
x^3 - 8x^2y^2 + y = 9x?

2007-10-28 03:17:57 · 3 answers · asked by a s 2

Determine all the asymptotes and all the incercepts (both x and y) of the rational function

F(x)= (2x^2 - 2) / (x^2 - 9).

and

F(x)= (x^2 - x +3) / (x+1)

2007-10-28 03:10:17 · 3 answers · asked by K Rose 3

Can someone tell me what is the order of operations for this problem?
11-10 divided by (10x9) =

2007-10-28 03:02:31 · 16 answers · asked by Anonymous

Low-voltage lighting is a popular feature of landscaping. Two pathways meet at 30 degrees to each other. One pathway has the lighting, and the first light is placed where the two paths meet. The distance between successive lights is 5m, and each has a range of effective illumination of 6m. For the second pathway, find, to the nearest tenth of a metre, the length that is
a.) effectively illuminated
b.) effectively illuminated by both the second and third light
c.) effectively illuminated by the third or fourth light.
Please show all workings.

2007-10-28 02:45:56 · 1 answers · asked by Anonymous

1)the lengths of the tangents from the potint (4,k) to the circle x^2 + y^2 = 9 are 4sqroot2. find the possible values of the constant k.

i think the answer is + or - 5 but am unsure on the working

2) show that the tangents from the point (3,-4) to the circles x^2 + y^2 + 2x - 4y + 4 = 0 and x^2 + y^2 +4x - 4y -2 =0 are equal in length

2007-10-28 02:38:27 · 2 answers · asked by Anonymous

cos2x=7sinx-3

2sin^2x=3cosx

Solve the folowing 0 2sin3x= -sq root 3

2007-10-28 02:32:02 · 1 answers · asked by cait 2

2007-10-28 02:31:09 · 5 answers · asked by Anonymous

w.r.t x

a)
y = 16^(x^2 + 2x - 5) = (2x + 2)16^(x^2 + 2x - 5)ln(12)

b)
f(t) = 600,000e^(.4(sqrt(t))

t = time

at what rate is this function growing when t=8?

f(8) = 600,000(-.4)e^(.4sqrt(8))ln(e)
f(8) = 600,000(-.4)e^(1.13)

would this be correct? id appreciate any help/comments on this. thanks.

2007-10-28 02:08:59 · 1 answers · asked by Mathema-what?! 1

The displacement 's' metres at time 't' seconds is given by:

s = 5cos3t + t^2 + 10 , for t => 0

a) Write doen the minimum value of 's'.

b) Find the acceleration, 'a', at time 't'.

c) Find the value of 't' when the maximum value of 'a' first occurs.

2007-10-28 01:55:32 · 2 answers · asked by Anonymous

I know the answer however how do I get to that answer??

2007-10-28 01:17:07 · 7 answers · asked by Becky B 1