SERIOUS ANSWER ONLY !
3 guys purchased a beer from a bar in 60 coins and shared 20-20-20 coins each and drink it and left . bar owner came and ask waiter that beer cost only 50 coins go and return 10 coins to them. the waiter goes and return them 2 coins each only and keep 4 coins to himself, so the beer cost them 18-18-18 coins each . so the question is :if beer cost them 18 coins each so 18+18+18=54 coins and the waiter have 4 coins which he dont gived back to boys so 4+54=58 ok! then where are the 2 coins are ? where are they who have them ,because boys have spend 60 coins and bar owner returnes 10 coin and waiter have 4 and boys have 6 = 60 ?
PLEASE ANSWER, I REALLY WANT IT .
2006-07-26
02:14:38
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10 answers
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asked by
Sidd
7