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7 answers

yes.

2007-11-11 05:10:53 · answer #1 · answered by Anonymous · 0 0

It's obvious, but since this is a food and drink, vegetarian & vegan forum...
lim ( ( x - sin x )/x^3 ) when x→0 = TVP

Edit:
I'm impressed that Zor and Madhukar can be so quick with they typing.

Zor uses the power series approximation and Madhukar uses trigometric identities and the squeeze thereom/sandwich thereom to come up with the answer.

However, for this forum, I stand by my answer.

2007-11-11 13:16:19 · answer #2 · answered by Dave C 7 · 2 1

lim ( ( x - sin x )/x^3 ) when x→0
By L'Hospital's Theorem,
limit
= lim [(1 - cos x) / 3x^2] ( x → 0 )
= lim 2sin^2 (x/2) / 12 (x/2)^2 ( x → 0 )
= (1/6) [ lim (sin (x/2) / (x/2) ]^2 ( x → 0 )
= 1/6

2007-11-11 13:16:30 · answer #3 · answered by Madhukar 7 · 3 1

Lancenigo di Villorba (TV), Italy

The MacLaurin limited series may be stopped at third level

sin x = x - (x^3) / 6 + ....

Starting from the previous writing, I will get you

((x - sin x)) / x^3) = 1 / 6

I hope this helps you.

2007-11-11 13:12:59 · answer #4 · answered by Zor Prime 7 · 2 0

yes

2007-11-11 13:11:22 · answer #5 · answered by Anonymous · 0 0

no it will collapse on itself

2007-11-11 13:15:51 · answer #6 · answered by iuberpwnyou 2 · 0 0

Vegan.


Wait, what?

2007-11-11 18:14:48 · answer #7 · answered by Jessica 4 · 0 0

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