yes.
2007-11-11 05:10:53
·
answer #1
·
answered by Anonymous
·
0⤊
0⤋
It's obvious, but since this is a food and drink, vegetarian & vegan forum...
lim ( ( x - sin x )/x^3 ) when xâ0 = TVP
Edit:
I'm impressed that Zor and Madhukar can be so quick with they typing.
Zor uses the power series approximation and Madhukar uses trigometric identities and the squeeze thereom/sandwich thereom to come up with the answer.
However, for this forum, I stand by my answer.
2007-11-11 13:16:19
·
answer #2
·
answered by Dave C 7
·
2⤊
1⤋
lim ( ( x - sin x )/x^3 ) when xâ0
By L'Hospital's Theorem,
limit
= lim [(1 - cos x) / 3x^2] ( x â 0 )
= lim 2sin^2 (x/2) / 12 (x/2)^2 ( x â 0 )
= (1/6) [ lim (sin (x/2) / (x/2) ]^2 ( x â 0 )
= 1/6
2007-11-11 13:16:30
·
answer #3
·
answered by Madhukar 7
·
3⤊
1⤋
Lancenigo di Villorba (TV), Italy
The MacLaurin limited series may be stopped at third level
sin x = x - (x^3) / 6 + ....
Starting from the previous writing, I will get you
((x - sin x)) / x^3) = 1 / 6
I hope this helps you.
2007-11-11 13:12:59
·
answer #4
·
answered by Zor Prime 7
·
2⤊
0⤋
yes
2007-11-11 13:11:22
·
answer #5
·
answered by Anonymous
·
0⤊
0⤋
no it will collapse on itself
2007-11-11 13:15:51
·
answer #6
·
answered by iuberpwnyou 2
·
0⤊
0⤋
Vegan.
Wait, what?
2007-11-11 18:14:48
·
answer #7
·
answered by Jessica 4
·
0⤊
0⤋