2007-12-18 11:23:49 · 21 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
Bronze is an alloy, the others are metallic elements.
2007-12-18 11:27:18 · answer #1 · answered by Anonymous · 7⤊ 1⤋
Bronze is the odd one out....all the others are pure metals whilst bronze is an alloy, or compound, of copper and tin.
2007-12-19 05:14:33 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Bronze is an alloy. All the rest are elements in the periodic table.
Cu = copper
Fe = iron
Sn = tin
Pb = lead
Bronze is generally a mixture of copper and tin, however it can also include other elements such as phosphorus, manganese, aluminium, or silicon.
2007-12-18 20:56:24 · answer #3 · answered by Thomas C 6 · 0⤊ 0⤋
Can one of them (copper perhaps) be found naturally occurring in nature (ie native) whereas the others need some kind of processing to produce.
If not the above I'd say bronze for the alloying reason given above)
2007-12-19 12:27:05 · answer #4 · answered by Steve C 6 · 0⤊ 0⤋
It could be bronze because it's an alloy and the others are elements, or it could be iron because it is attracted to a magnet but the others aren't.
2007-12-18 19:38:34 · answer #5 · answered by Anonymous · 0⤊ 1⤋
Iron, it is the only ferrous metal in the group,or Bronze which is the only mixed metal, therefore non elemental, take your pick !
2007-12-22 04:46:29 · answer #6 · answered by Brian E 2 · 0⤊ 0⤋
Bronze, because you don't win the medals made of other listed item.
2007-12-19 08:48:28 · answer #7 · answered by Irfan 2 · 0⤊ 0⤋
Iron is magnetic, the others aren't.
Iron suffers destructive corrosion in normal weather conditions, the others form protective oxides.
2007-12-19 02:18:34 · answer #8 · answered by Tom V 6 · 0⤊ 0⤋
Iron (Fe) is the odd one out because all of the others are non-ferrous
2007-12-22 18:12:13 · answer #9 · answered by JOHN O 2 · 0⤊ 0⤋
you could also say the tin (Sn) is the odd one because Sn is a semiconductor and all the others are metallic conductors of electricity.
2007-12-18 20:19:22 · answer #10 · answered by Gary H 7 · 0⤊ 1⤋