Glenda drops a coin from ear level down a wishing well. The coin falls a distance of 7.00 m before it strikes the water. If the speed of sound is 343 m/s, how long after Glenda releases the coin will she hear a splash?
2007-12-04 19:48:18 · 5 answers · asked by HGA 3 in Entertainment & Music ➔ Jokes & Riddles
OMG, this should be in Physics sections not riddles, but wht the heck, here is the answer:
1st calculte the time needed so the coin hit the will:
t1= d/V2, d=7m
mgh = m(V2^2 -V1^2), V1=0, h=7
9.8*7 = V2^2 -----> V2 =8.3
t1= 0.84 sec
now the time so the sound to get to Glenda
t2= d/Vs Vs =343m/s d=7
t2= 0.02 sec
t= t1+t2 =0.86 sec
it will take
OMG, I can't believe tht i'm actually answeing this, Errrrrrg
U better give me 10pts as best answer, bcs i'm the only who had bothered himself answering u.
plz tell me tht it is not a riddle or i'll really feel stuiped.
2007-12-04 20:24:47 · answer #1 · answered by Light Shielded By Dark 5 · 3⤊ 0⤋
if glenda jumps down the well as she drops it she wont hear the coin splash as the noise from her hitting the water will cover the sound
2007-12-05 01:16:55 · answer #2 · answered by mobile auto repair (mr fix it) 7 · 0⤊ 0⤋
The well is dry, she be waiting a long time.
2007-12-04 20:26:50 · answer #3 · answered by Regwah 7 · 0⤊ 0⤋
0.0204 seconds after it hits the water, so lets say, 1.5204 seconds approximately.
At a guess.......!
Very best regards
Geordie
2007-12-04 20:35:34 · answer #4 · answered by Grizz 5 · 0⤊ 0⤋
The well is dry....so there will not be a splash...!!
2007-12-04 21:18:50 · answer #5 · answered by Unknown Person 2 · 0⤊ 0⤋