to measure the speed of the jet stream, a weather plane left its base at noon and flew 800 km directly against the stream with an air speed of 750 km/h. It then returned directly to its base, arriving at 2:24 p.m. what was the speed of the jet stream?
2007-12-04 09:28:18 · 8 answers · asked by Anonymous in Cars & Transportation ➔ Aircraft
Tell the pilot to look at the Garmin GPS, it will tell you.. or
to be a real stickler..
First, speed is measured in knotts, not Km/h for aircraft, the difference is because they measure nautical miles, not Kilometers, which is based on the curvature of the earth, so the problem is faulted there to begin with. Next, Airplanes fly at indicated airspeed, so he flew at the same speed each way, but his ground speed was different. Also,
what altitude, as the winds change with alititude, and if the aircraft was flying in the jet stream, it would have to be higher than FL180, which means that they were on an IFR flight plan, and IFR cruising alititudes are required. So the alititude that he flew in the wind is not the same altitude that he flew back. Also this difference in altude, is dependant on if the aircraft is RVSM or not. On takeoff and landing, he could not maintain the same speed as he did at altidude, because they can not go over 250KIAS below 10,000MSL, or above 200kias in Class B, C, D and did he get vectored on approach, have to do a procedure turn for an insturment approach.
So tell the teach he flew at 450KIAS, and if they tell you your wrong, spit this out.
2007-12-04 10:39:55 · answer #1 · answered by captsead0nkey 6 · 0⤊ 1⤋
There are too many unaddressed variables to answer this
question. The weather plane required time for vectoring, time
for a long climb to about 40000', time to turn around, time for
a lengthy descent, time for traffic avoidance and landing. I
hope the weather plane had some advanced instrumentation
because they didn't do it by airspeed and clock. Besides,
the problem states that the plane travelled slower with the
wind than against. An hour and 2 minutes against the wind
and an hour and 22 minutes with the wind.
2007-12-05 10:38:01 · answer #2 · answered by Aerostar 4 · 0⤊ 0⤋
It depends upon the weather, and how many people are on the plane and if they are eating a meal or not... oh, and if that meal is kosher or not.
What are you learning by coming here and asking others to do your homework? Do you want to serve burgers for a living when your 40 or what?
2007-12-04 09:32:00 · answer #3 · answered by jimstock60 5 · 0⤊ 1⤋
the sum of three angles of an triangle is one hundred eighty degree, and something of two angles for an isosceles triangle might desire to be equivalent, hence, the respond might desire to be: enable x be an perspective, Vertex is (x+x)-40 2x+{(x+x)-40}=one hundred eighty 2x+2x=220 4x=220 x=fifty 5 so, the two angles on the backside would be fifty 5 each, and the vertex is (fifty 5+fifty 5-40)=70 in case you upload all the angles jointly, fifty 5+fifty 5+70=one hundred eighty merely bear in mind that the sum of three angles jointly in an triangles continuously equivalent to one hundred eighty regulations of thumb: 2 angles ought to continuously be an identical for isosceles trianlge One perspective might desire to be ninety for ideal perspective Triangle
2016-10-19 04:15:32 · answer #4 · answered by saulsbery 4 · 0⤊ 0⤋
2 hrs before your luggage
2007-12-04 09:33:10 · answer #5 · answered by irish_matt 7 · 0⤊ 1⤋
you would be better off asking this question in the math category
2007-12-04 10:46:20 · answer #6 · answered by Kevin H 3 · 0⤊ 1⤋
0.93754 speed
2007-12-04 09:32:41 · answer #7 · answered by Anonymous · 0⤊ 1⤋
sorry I have no clue... toughy...
2007-12-04 09:30:33 · answer #8 · answered by Jason K 5 · 0⤊ 1⤋