2007-11-11 04:12:30 · 4 answers · asked by lunya 1 in Science & Mathematics ➔ Engineering
Take one 100 Watt bulb on a 120VAC circuit. That produces 100Watts of light.
Put 2 100Watt bulbs on a 120VAC circuit and assuming that their resistance was constant ( which is not true) then they will draw 1/2 the current of one 100 Watt bulb and each bulb with then have 1/2 current and 1/2 voltage or 1/4 of the power of 1 100 Watt bulb, so the total power from both bulbs in series would be 1/2 the power or 50 Watts.
2007-11-11 04:19:35 · answer #1 · answered by rscanner 6 · 1⤊ 0⤋
The more resistance, the lower the current for a given voltage. Two bulbs in series are like two resistors in series. They will no longer have full current for proper operation.
That is why we put bulbs in parallel.
2007-11-11 12:34:23 · answer #2 · answered by Warren W- a Mormon engineer 6 · 1⤊ 0⤋
hi , my name is jax . am saying is from expericence ok . two bulb in series will share the total income power togetter ok but those in parrallel connection will has indepentent of income power so two bulb are like resistance to given voltage in a cuicuit .ok am studing electrical /electronics ok
2007-11-11 13:06:51 · answer #3 · answered by ike e 2 · 0⤊ 0⤋
resistance
2007-11-11 12:19:28 · answer #4 · answered by railer01 4 · 0⤊ 0⤋