I needed help figuring out the following problem. all help is greatly appreciated :)
The velocity of the transverse waves produced by an earthquake is 8.9 km/s, and that of the longitudinal waves is 5.1 km/s. A seismograph records the arrival of the transverse waves 68 s before the arrival of the longitudinal waves. How far away is the earthquake?
2007-10-30 13:42:53 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
A) find time 't' (in seconds):
8.9 * t = 5.1 * (t + 68)
B) once you find t from the above equation, find the distance:
8.9 * t = d (in km)
.
2007-10-31 06:13:00 · answer #1 · answered by tlbs101 7 · 0⤊ 0⤋
i do no longer a have paper to jot down this problem so I make an apology i'm no longer going to paintings all of it the way out yet i can inform you a thanks to set it up. I is your intensity so that you'll be able to easily plug that contained in the gadgets are stunning, plugging in 10^12 will supply you your low answer and a million.0 will be your extreme. Your frequency in 3 kHz, i have self assurance you pick to enter that into the equation as 3300hz and ensure you sq. it, the density of air is given, that's density and the gadgets are o.k., ultimately the speed of the wave is merely the speed of light so that's about 3x10^8 m/s. merely plug in all of those values and ensure for A^2 and then sq. root it and also you should get the stunning solutions. i desire this enables!
2016-10-23 04:20:03 · answer #2 · answered by wexler 4 · 0⤊ 0⤋