60 meters = 197 feet /2.31 feet per psi = 85 psi.
So the horsepower would depend upon how many Gallons Per Minute (GPM) that you want to pump at a pressure of 85 psi.
Brake HP = GPM*H/3960*pump efficiency
where H = the pressure in feet of water = 197 for this case.
So for your case, assuming a pump efficiency of 0.85 (85%)
Brake HP = GPM*197/3960*0.85
Brake HP = GPM*0.0585
Technically you should also add some additional pressure head to your solution to account for flow losses in the piping, if you want to maintain a head of 60 meters at the pipe outlet.
2007-10-27 16:24:02
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answer #1
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answered by gatorbait 7
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It will depend on factors like what flow rate is required, what is the material and its smoothness that the pipe is made from, what is the cross sectional area of the pipe, and what is the efficiency of the motor that will be driving the pump.
Just to get the water that high you need to generate about 2 atmospheres of pressure but if you are just spitting it out of a skinny tube then you can get by without much pump horsepower. For a practical application you need to consider those other factors above.
2007-10-27 16:14:41
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answer #2
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answered by Rich Z 7
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Your data is lacking....we need volume of water to be lifted or the discharge rate that you want. But assuming 1 cubic meter of water..
1m^3 = 1000 kgs
Force required = mass* gravitational force
= 1000*9.82
= 9820 kg.m/sec^2 (newton)
Assuming that you want to do this in 1 minute:
Horsepower (hp) = (force*distance)/time
= (9820*60)/60sec = 9820 newto-meter/sec
= 9820 joule/sec or watts * 1hp/746watts
= 13.16 hp
or you need around 13.5hp pump or you may have lower pump capacity if you want longer time.
2007-10-27 18:01:23
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answer #3
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answered by Synchronizers 3
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depends on the cross sectional area of the pipe
2007-10-27 16:08:40
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answer #4
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answered by MB 2
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