on the back of the scratcher there is a number 1:3.69 odds of win any prize, is this a order of which card number will be next to win
2007-10-11 18:57:35 · 5 answers · asked by ChristiCarlClub 2 in Games & Recreation ➔ Gambling
No. Otherwise in your example you could buy four tickets and definitely win one of them.
The fact is you could buy 100 at the same time and not win a single one. It's unlikely, but possible.
All those odds are saying is that in a batch of say 100,000 tickets 27,100 of them will be winners. Of course many of those winners are just winning your money back.
2007-10-12 02:14:01 · answer #1 · answered by ZCT 7 · 0⤊ 0⤋
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2016-05-15 18:51:55 · answer #2 · answered by ? 2 · 0⤊ 0⤋
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2016-05-01 20:32:48 · answer #3 · answered by Anonymous · 0⤊ 0⤋
I would say no, other wise it would be a solid number, like 1:3 or 1:4. If it were in order, imagine how many people could abuse it?
2007-10-11 19:06:31 · answer #4 · answered by im_irish_mike 2 · 0⤊ 0⤋
doubt it, that is the odds of all the people playing, but the
lotto itself is *supposed* to be random
just like at vegas where they have that little screen next to the roulette table that shows which number it has passed, when in reality it is random and the same numbers can come up again
2007-10-11 19:05:18 · answer #5 · answered by Anonymous · 0⤊ 0⤋