A man who is heterozygous for Huntington's Disease marries a normal woman. What percent of their offspring will be normal? What percentage will have Huntintgton's Disease?
2007-10-11 15:13:14 · 3 answers · asked by damigurl05 1 in Science & Mathematics ➔ Botany
H - Huntington's Disease allele
h - normal allele
Man: Hh
Woman: hh
Offspring:
P(normal) = 0.50
P(affected) = 0.50
Therefore we predict that half (50%) of the offspring would have Huntington's Disease.
2007-10-11 15:29:07 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Every child of a person that actually has Huntingtons, has a 50-50 chance of himself getting the disease, even if the other parent is normal. That person as well has a 50-50 chance of passing it to his/her children. The sad part about Huntington's is that it does not usually have an onset of neurological problems until well after a person marries and has had children. As I remember, there are now tests to see if one is carrying the gene. However, many choose not to check... the realization that they will indeed progress to it is of course devastating. Many couples now who have it in their families are getting tested or are opting out of having children.
2007-10-11 15:33:10 · answer #2 · answered by April 6 · 0⤊ 0⤋
Since Huntington's is a Dominant Gene, and the father is Heterozygous, there is a 50-50 chance. If he were homozygous, there would be 100%.
2007-10-11 16:34:45 · answer #3 · answered by charonnisis 3 · 0⤊ 0⤋