How do i work out if an electronic component is suitable for the current rating of my circuit?

Question

I am trying to decide which microswitches I can use on my electronic circuit and have noticed a value in the component catalogs for 'maximum current' how do I work out if ttey are compatable with my circuit. For example if I want to use a relay with a maximum current of 2A how do I work out if this fits within the current rating of my circuit -- I assume I need to work out the current/ampage of the circuit?? Thanks in advance

Answer 1

There will be some source voltage that a load is connected to -- through the relay contacts. Divide the source voltage byt load resistance to get the current flowing through the contacts.

Be sure to give yourself some lee-way. If you want to pass 2 A make sure the contacts are rated for at least twice that to be on the 'safe' side.

Example: 12 volt source, load is a light bulb rated for 12V and 30W, that's 2.5A. I would use a 5A contact.

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Answer 2

The 60Hz house frequency can not be changed by the use of an LRC circuit. Applying an external frequency source to an LRC tank circuit will not change the frequency of the external source nor the resonant frequency of the tank circuit. Resonant frequency = 1/[2pi (sq rt LC)]. Therefore resonant frequency can be varied by changing the value of L or C. All tank circuits have a specific resonant frequency at which they will start to oscillate only if and when they are supplied a quantity of electrical energy from an external source of sufficient magnitude to start oscillations.. The tank circuit will continue to oscillate at it's resonant frequency until the external source of energy is removed and will then continue to oscillate at it's resonant frequency until all the remaining energy from the external source is dissipated in the internal resistance of the tank circuit. Even though every tank circuit has a specific resonant frequency, no tank circuit will oscillate at it's resonant frequency without an external energy source to start oscillations and to replace the energy dissipated in internal resistance during each cycle of oscillation.

Answer 3

Like they say, use twice the switch you need. One reason is that if you're passing AC, the peak current will be higher than the rms current you probably calculated. And it leaves you some margin so the switch will still be good as it ages.

Answer 4

Voltage = current x resistance.
so current is voltage divide by currrent
therefore current is voltage divide by resistance.

Makesure that the relay is capable of double the maximum current it takes otherwise it will overheat and burn the contacts, due to arking.

Answer 5

I=V/R

you did not give enough details
AC or DC ?
inductive load?
capacitive load?

since you seem ill equipped in electronics, take care not to electrocute yourself

Answer 6

e(volts)=I(current)xR(resistance) I=e divided by R R=e divided by I then give a little added leway...

Answer 7

try really hard

Answer 8

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