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29 answers

You, only you were going to the forum!!!

2007-09-25 02:42:04 · answer #1 · answered by Anonymous · 0 0

7

2007-09-25 09:46:00 · answer #2 · answered by Anonymous · 0 0

Your question is not clear; However for your question "How many were going to Forum", the answer is as many people as were heading towards it.

The other way is, if you are going together with a man of 7 wives, each having 7bags, each of 7bag containing 7 cats and each kat having 7 kittens, then how many of you all are going to Forum? Then the answer is 2753. The break up is 343 Big Cats, 2401 Kittens put together 2744, 7 wives and their 1 husband and you!!

All put together 2753 of you were going to Forum.

I think the actual question goes this way:
There is a bus with 7 girls inside,
Each girl has 7 bags,
Inside each bag, there are 7 Big cats,
Each Big cat has 7 small cats,
All cats have 4 Legs each!

Question: How many Legs are there inside the bus?
Now find out the number of legs....

2007-09-25 23:42:36 · answer #3 · answered by Mohan K 2 · 1 0

The man,his 7 wives and 49 cats went to the forum.

2007-09-26 06:38:24 · answer #4 · answered by Anonymous · 0 0

The man,his 7 wives and 49 cats went to the forum.

2007-09-25 11:21:53 · answer #5 · answered by Anonymous · 0 0

8

2007-09-25 10:40:29 · answer #6 · answered by suhana 3 · 0 0

1 wife has 7 bags n 7 cats in each.there fore 49 cats for 7 wives.
Each cats has 7 kits.Therefore 49 * 7 = 343.
1 man + 7 wives + 343 cats & kits + u ===> 352

2007-09-26 01:12:45 · answer #7 · answered by sprite 6 · 0 0

When I means, 1 person was going to the forum

2007-09-25 10:43:31 · answer #8 · answered by wcs_n_ms 2 · 0 0

I'm sure there will have been thousands on the forum but in this riddle there's you and the man, answer being 2??

2007-09-25 09:42:27 · answer #9 · answered by Anonymous · 0 0

Just one, You only met the man on the way but he is not necessarily going to the forum

GOOD ONE, You had me pull out the calculator for that one !

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2007-09-26 10:06:36 · answer #10 · answered by Steven H 5 · 0 0

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