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What is the current through the 3.6k resistor? Total resistance in the circuit is 5k, I think total current is 2 mA but I'm having trouble remembering how to calculate current through parts of the circuit and over resistors.
2007-09-23 03:14:53 · 1 answers · asked by Chris 2 in Science & Mathematics ➔ Engineering
Also calculated that Va = 6 V, Vb = 3 V, and Vc = 1.8 V
2007-09-23 03:17:32 · update #1
Yes, it's 5K and the current from the battery is 2 ma. That means the drop across the 2K resistor is 4V and Va = 6V. Then the 12K resistor will have 1/2 ma flowing through it and the remaining 1.5 ma will flow to the right causing a drop of 3V across the 2K resistor. That means there will be 3V at Vb and a 2.4K and a 3.6K resistor in series across it will be 6K for a half ma through the circuit and .5 ma through a 3.6K resistor will produce 1.8V across it.
It's just all repeated application(s) of Ohms Law(s) and Kirchoffs Law(s).
Doug
2007-09-23 03:44:04 · answer #1 · answered by doug_donaghue 7 · 0⤊ 0⤋