2007-09-19 04:23:33 · 10 answers · asked by taggy 1 in Health ➔ Diseases & Conditions ➔ Diabetes
Yes, I do! You have to be getting medication for your diabetes (I take metformin), then you get all medication free. Most GPs will be happy to prescribe Viagra, as erectile problems are a recognised side-condition of diabetes.
2007-09-19 04:28:45 · answer #1 · answered by Avondrow 7 · 1⤊ 0⤋
No, sorry man, mostly seems not, altough some daibetics seem to get free somehow. Just talk to your GP, if youy have ED you will get a free ED trial pack of viagra cialis and levitra for free anyway.
Also check out the forums at http://www.viagrausers.blogspot.com
It is an online community of viagra cialis and levitra users, may be something there.
There is price comparison of cheapest online pharmacies for ed meds on the site, too.
2007-09-19 04:29:31 · answer #2 · answered by Anonymous · 0⤊ 2⤋
Absolutely, yes ... as long as you've been diagnosed as suffering with erectile dysfunction.
Having said that, there are circumstances where viagra is contraindicated. i.e., if you take nitrates for angina (Glycerine Trinitrate, or GTN)
2007-09-19 13:57:02 · answer #3 · answered by micksmixxx 7 · 0⤊ 0⤋
Yes
2007-09-19 04:31:25 · answer #4 · answered by Roggles 4 · 1⤊ 0⤋
the answer my dear old friend is no. in general people with diabetes take other pills e.g. levitra rather than viagra. do we get it for free? nope. have to pay.
2007-09-19 10:56:58 · answer #5 · answered by Ivan E. Cao-Berg 2 · 0⤊ 1⤋
Yes as long you get a doctors prescription and have problems with erectile dysfunction.
2007-09-19 04:33:18 · answer #6 · answered by Anonymous · 0⤊ 0⤋
Only if the doctor prescribes it. Diabetics don't have to pay prescription charges.
2007-09-19 04:31:37 · answer #7 · answered by Anonymous · 0⤊ 1⤋
Yes, only if they work for Hugh Hefner.
2007-09-19 04:36:21 · answer #8 · answered by cidyah 7 · 0⤊ 2⤋
too much sugar
2007-09-19 04:27:22 · answer #9 · answered by Anonymous · 0⤊ 2⤋
no
2007-09-19 04:27:14 · answer #10 · answered by essentiallysolo 7 · 0⤊ 2⤋