Why are reacting forces important to counter dead loads.?

Question

Can some one give me some examples please. thanks

Answer 1

Dead loads are static loads, which means they are stand-still loads, they aren't moving or flying.


Consider a rock on the ground outside, the rock has a certain mass (we'll call M) and obviously the Earth's gravity (g). So we find out the FORCE by using Newtons Law

F = Mg (or Ma...)

However, the rock isn't being constantly pummeled into the ground, as a matter of fact it is standing still. So we know that there must be an EQUAL but OPPOSITE REACTION FORCE being applied to the rock UPWARD.

F = M (-g)

Another demonstration is to put your hands together close to your chest, elbows bent, with your fingers pointing up. Now push hard....In most cases your hands will stay in the same place. This shows that you had your right hand with a mass (M1) and your left hand with a mass (M2) and we assume each hand has an EQUAL and OPPOSITE acceleration applied (obviously one hand is pushing one way, and the other hand in the opposite.)

Answer 2

I assume the dead loads are not in-line with the load point
or not stable (but what should I know ...I do electronics)

archway
bridge

Answer 3

Simply put:
To keep them from becoming live loads
somewhere else.