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i wonder... okay, imagine that you are in an airtight room... which is made up of mirror then, you turn on the light and turn it off.... what do u think will happen? will the lights continue shine... or the room will turn dark... or any other possibility??? please... don't put any harsh word! thanks...

2007-07-01 23:17:32 · 4 answers · asked by kit 3 in Science & Mathematics Engineering

does light occupied space?

2007-07-02 18:22:08 · update #1

4 answers

Once you turn off the light, the room will be dark.

The mirrors and lack of air won't affect that.

2007-07-01 23:22:41 · answer #1 · answered by Anonymous · 2 0

not until you can design a perfectly reflective mirror will anything happen except the room getting dark as soon as the lights go out. Even the most advanced mirror we have absorbes some of the light energy when it bounces off. Even then some of the the light energy will be absorbed by the the air inthe room.. (You said airtight not a vaccuum)

2007-07-01 23:31:18 · answer #2 · answered by Lost in Merryland 4 · 1 0

The light will extinguish almost instantaneously as the mirrors are not perfectly efficient, and will absorb energy, re-radiating it as heat. (Consider that all surfaces we know are reflective to some degree, and when you turn the light off in a normal room it becomes dark so quickly that no one has been able to time the process, to my knowledge.)

2007-07-01 23:25:41 · answer #3 · answered by Helmut 7 · 1 0

it will go dark eventually as the source of the energy will fade away.

2007-07-01 23:21:26 · answer #4 · answered by Anonymous · 1 0

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