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A circuit is set up in such a way that with a 72 volt source and three resistors in series a current of 1.33 A is drawn. What is the value for each of the resistors if they are all identical?

2007-04-18 16:04:36 · 6 answers · asked by lucan1958 1 in Science & Mathematics Engineering

6 answers

How can you become an engineer if you cannot understand Ohm's law? V = IR. In your case, R = 3r; substitute and solve for "r".

2007-04-18 16:13:18 · answer #1 · answered by noitall 5 · 0 0

Resistance = Voltage ÷ Current

R = 72 ÷ 1.33 = 54.14 Ώ
54.14 ÷ 3 = 18.05 Ώ each.

2007-04-19 13:46:21 · answer #2 · answered by Norrie 7 · 0 0

Approximately 18.05 ohms each

I originally had put in 18.5 ohms and realized that I had
fat fingered the answer by leaving out the 0

2007-04-18 23:13:46 · answer #3 · answered by justgetitright 7 · 0 0

Ohms law: R = E/I. 72 / 1.33 = 54.135 ohm total. If they identical, divide by 3 and you get 18.045 ohms.

2007-04-19 01:12:20 · answer #4 · answered by scott p 6 · 0 0

By ohm's law
V=IR,here we have three identical resistors
=> V=I(3R)
3R=V/I
3R=72/1.33
3R=54.14

So, R=18.01Ohms

2007-04-18 23:47:04 · answer #5 · answered by salai_arasu_m 2 · 0 0

Rt = E/A

R1=Rt/3

2007-04-18 23:21:01 · answer #6 · answered by producer_vortex 6 · 0 0

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