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A person hooks a 12 Volt battery to a circuit with a total resistance of 3.5 ohms, what is the current in the circuit?

2007-04-18 15:54:20 · 6 answers · asked by lucan1958 1 in Science & Mathematics Engineering

6 answers

Use V=IR

In this case:
V=12
R=3.5

So putting it back into the equation:
12=I(3.5)
or
12/3.5 = I
where I = current.

So in turn:
Current =3.428A (Amps)

2007-04-18 15:59:29 · answer #1 · answered by Anonymous · 0 0

What a coincidence. There was just another problem with 10 times the voltage and 10 times the resistance in which Ohms law said it is 3.4 amps.

It sounds like a variation of the same homework problem.

2007-04-18 23:43:42 · answer #2 · answered by Rich Z 7 · 0 0

v = voltage
r = resistance
i = current


v = r i

i = v/r => i = 12 volts/3.5 ohms = 3.4 amperes

2007-04-18 22:59:51 · answer #3 · answered by frank 7 · 0 0

v = i*r

12 = i * 3.5
i = 12/3.5

i=3.429 amperes

2007-04-18 23:00:18 · answer #4 · answered by anotherbsdparent 5 · 0 0

V = IR

I = V/R

12/3.5

I= 3.45A

2007-04-18 22:57:53 · answer #5 · answered by 2 · 0 0

you couldnt figure that out?

2007-04-18 23:02:50 · answer #6 · answered by mnb 1 · 0 0

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