You do 150 J of work on a machine and the machine does 90 J of work as a result. What is the efficiency of the

3 ⤊

2007-04-09 09:46:59 · 4 answers · asked by Svetlana D 1 in Science & Mathematics ➔ Engineering

90/150 = 0.6

60% efficient

efficiency = work out / work in

2007-04-09 09:51:30 · answer #1 · answered by tlbs101 7 · 2⤊ 0⤋

150 Joints of work is not a lot of work. You try to smoke 150 Js and then do ****. Won't. Happen.

2007-04-09 16:53:44 · answer #2 · answered by ohmygodapirate 2 · 0⤊ 1⤋

150 Joules of work go in
90 Joules of work go out...

efficiency = work out/ work in

90/150 is 60% efficiency.

2007-04-09 16:53:47 · answer #3 · answered by Tron 2 · 1⤊ 1⤋

the efficiency =
output / input =
90J / 150J =
0.60 = 60%

Th

2007-04-09 18:32:01 · answer #4 · answered by Thermo 6 · 0⤊ 0⤋