what would be the overcurrent protection device and cable size copper of 350 kw.single phase or 3 phase 220 vo

Answer 1

Holy crap.

350000=220*I
I=350000/220
I=1590 Amps. Single phase.

Depending on how it is installed, 2000 AWG could get you there.


here is the formula for 3 phase.

I= sqrt [(tc-(ta+delta td)/((rdc(1+yc)rca)]

tc=cond temp in C
ta= ambient temp in C
delta td= dielectric loss temp rise
yc=skin effect and proximity effect
rca=effective therm res. between cond and surrounding ambient
rcd= dc res of cond. at tc