Is the ATSC tuner an antenna in itself? When buying an LCD TV with the ATSC installed, will I need to buy an antenna? That's my question. I'm considering buying an LCD TV. My thing is, I don't want to have to pay a monthy fee to some cable company, just to see local channels.
I've read about LCD/HD TV's, and in a sense, am confused. I think I may hold off until Sept 2008 to buy an LCD TV with a ATSC tuner built in, since analog TV will be turned off by Feb 2009.
2007-04-09 03:58:42 · 5 answers · asked by Sam Darren 3 in Consumer Electronics ➔ TVs
yes as the tuner decodes the data the antenna receives. get a wideband UHF/VHF antenna which will cover you for all channels including HD
2007-04-09 04:20:29 · answer #1 · answered by Anonymous · 0⤊ 1⤋
You will need some kind of antenna depending on where you are with respect to the TV transmitters. You may be able to get by with an indoor antenna in a strong signal area. This is considered the best: http://www.zenith.com/sub_prod/product_Display.asp?cat=&id=131
Go to http://www.antennaweb.org/aw/welcome.aspx
to get an idea of what you may need,
2007-04-09 13:25:52 · answer #2 · answered by gp4rts 7 · 0⤊ 1⤋
From what I know about this, I would have to say yes. It will also depend on whether or not the local channels in your area decide to broadcast over-the-air in digital. This may or may not happen. I live near Jacksonville, FL which is a pretty big city and I have started to see notices appearing on the local FOX affiliate stating that certain actions must be taken before Feb. 2009 (probably meaning getting the equipment you are asking about.)
2016-05-20 23:27:32 · answer #3 · answered by Anonymous · 0⤊ 0⤋
yes you still need an antenna. an atsc tuner is still a form of signal reciever, only it recieves signals at a higher frequency than regular tv.
2007-04-09 04:12:57 · answer #4 · answered by scor2_21 3 · 1⤊ 1⤋
You have to use an antenna to get signal. Recommend using a HDTV tuned antenna to get best results.
2007-04-09 04:08:27 · answer #5 · answered by Anonymous · 0⤊ 0⤋