2007-03-25 17:17:22 · 12 answers · asked by chingonSD 1 in Sports ➔ Boxing
Again! There are like 5 classes to put boxers in. Roy Jones Jr. could have been the best cuz he is in 3 classes. Chavez, cuz of the 90 and 0 thing. But Ali is the best cuz he would beat you before you got in the ring! It’s hard to say. Each one of these guys are the best in their weight classes along with the gay A55 golden boy. I don’t like him but he is still one of the best fighters in boxing now, and I hope he wins his nest fight!
2007-03-25 20:36:55 · answer #1 · answered by maestrosantana 5 · 0⤊ 1⤋
No, he's not. There are a lot of boxers who are better than Chavez in history P4P. The best ever is probably Sugar Ray Robinson.
2007-03-25 19:23:23 · answer #2 · answered by Chao 2 · 0⤊ 1⤋
Chavez was technically skilled and fundamentally sound, perhaps one of the top 10 pound-for-pound fighters of all time, but he's not the best in history. He didn't have good competition until the latter part of his career, and since he relied too much on technical skills, his fights were often boring and lacking in excitement.
2007-03-25 18:18:02 · answer #3 · answered by bundini 7 · 1⤊ 1⤋
No, hands down Ali. Sugar Ray Robinson was in a totally different weight class
2007-03-25 20:40:45 · answer #4 · answered by Yeezy 3 · 0⤊ 2⤋
No, because Sugar Ray Robinson is. Ask Ali.
2007-03-26 00:33:07 · answer #5 · answered by gone 6 · 1⤊ 1⤋
Chavez was overrated. He stole the title back from Frankie Randall when he quit in his corner.
2007-03-25 22:32:21 · answer #6 · answered by Anonymous · 0⤊ 1⤋
Not even close. He might be the best of our generation, but the best is without a doube Sugar Ray Robinson.
2007-03-25 18:28:01 · answer #7 · answered by dropkickchester 3 · 1⤊ 2⤋
First its Muhammed Ali and then Chavez
2007-03-25 17:20:46 · answer #8 · answered by vegeta 2 · 1⤊ 3⤋
He is not cuz Sugar Ray Robinson is.
2007-03-25 19:33:42 · answer #9 · answered by michael w 2 · 0⤊ 1⤋
ROFLMAO....you must be young...good luck in your boxing history classes
2007-03-25 17:25:40 · answer #10 · answered by Michael K 5 · 0⤊ 1⤋