You have eight billiard balls. One of them is "defective," meaning that it weighs more than the others. How do you tell, using a balance, which ball is defective in two weighings?
2007-03-25 11:23:03 · 5 answers · asked by ws 3 in Entertainment & Music ➔ Jokes & Riddles
Put three balls on each scale; set two aside. If the heavy ball isn't on one end of the scale, it's on the sidelines. Either way, another weighing will find it.
2007-03-25 11:33:23 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Place 3 balls on each side of the scale. If the balance is equal, then simply weigh the two remaining balls to see which is heavier. If one of the groups of 3 is heavier, remove one ball, set it aside, and weigh the other two. If they are equal, the ball you set aside is the defective one. If one is heavier, of course it is the defective one.
2007-03-25 18:32:34 · answer #2 · answered by radioflyer 5 · 1⤊ 0⤋
put 3 on each side if they are the same one of the 2 left overs are the bad one try again with those 2 1 on each side or if when you put 3 on each side 1 side is heavier take 2 of them and try again if the same its the extra fron first 3
2007-03-25 18:39:25 · answer #3 · answered by gregs111 6 · 0⤊ 0⤋
omg, I just gave a book of that kind of questions to my friend.... It had the same question. It also has many other interesting ones. Please keep this question open, so I can answer when she gives the book back.. please....... thanx, there are sooo many cool questions....
2007-03-25 18:35:01 · answer #4 · answered by Joka B 5 · 0⤊ 0⤋
i don't know
2007-03-25 18:31:40 · answer #5 · answered by Meep 3 · 0⤊ 1⤋