2007-03-25 10:57:37 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
Curiously the answer is not that the rubber band flies furthest at a 45 degree angle. Trajectory tables for all types of projectiles have confirmed that an object flies farthest with an angle of 42 degrees. An object theoretically flies farthest from an angle of 45. But since the curvature of the earth falls away from the trajectory of an object, an object flies farthest with the angle at 42. It would be almost impossible to measure a rubber band's trajectory at 42 as compared to 45 to determine which flies farthest. The difference between 42 and 45 degree angle of departure with a rubber band and the total distance traveled is negligible. Trajectory tables are extensively covered in Hatchers Notebook.
2007-03-25 16:43:09 · answer #1 · answered by Anonymous · 0⤊ 0⤋
A rubber band or any projectile for that matter will fly the farthest when shot at an angle of 45 degrees because it is the halfway between 0 and 90 degrees. A projectile at 0 and 90 degrees will travel a distance of zero. The distance will increase from zero until the angle reaches 45 then will decrease back to zero.
2007-03-25 18:08:37 · answer #2 · answered by wdeason07 1 · 1⤊ 1⤋
Give it an experimental try.
Get outside. Get a hose. Make water throttle through it.
Give the hose different angles. You'll see that at 45° you get the furthest reach. At 90° you get wet.
The water is afflicted by to two forces, one out of the hose, and one other constant, pulling vertically down, gravity. Now go to the formulas. Rubber band, bullets, stones, all make the same trajectory. But hurt in different degrees.
2007-03-25 20:22:09 · answer #3 · answered by fedebicho 3 · 0⤊ 0⤋
If you look at the equations of projectile motion on a flat plane, the range R is given by t*vCos(theta), where t is the time of travel, v is the initial velocity and theta is the angle of projection.
The rubber band is also travelling vertically. The time taken to reach max height (where velocity = 0) can be written as t = vSin(theta)/g. The band travels up and down, therefore the total time taken for motion is 2vSin(theta)/g.
Combining this with the previous equation gives
R = (2*v^2*Sin(theta)*Cos(theta))/g
The value of theta which maximises this is theta = 45 degrees.
2007-03-25 18:04:53 · answer #4 · answered by dudara 4 · 2⤊ 0⤋
It is the angle for all things ,a cannon ball or what ever will travel the furthest at 45 deg.
2007-03-25 20:45:58 · answer #5 · answered by JOHNNIE B 7 · 0⤊ 0⤋